What Volume Of 12.0 M Hcl Is Required To. What volume of 12.0 m hcl is required to prepare 16.0 l of 0.250 m hydrochloric acid? None of the above answered:.
None of the above answered:. 12 m = 12 moles hcl per 1 liter of solution.so 12 moles/ 1 liter = 3 moles/ x liters. Web solution for what volume of 12.0 m hcl is required to make 75.0 ml of 3.50 m hcl? Mass of hcl in one molar solution which is the molar mass is 36.5. X = 0.25 liters of 250ml. We all know that density = mass/volume. Web v₁ = 21.9 ml (following scientific notation, round to the nearest tenths) therefore, the volume of the 12.0 m hcl required is 21.9 ml. What volume of 12.0 m hcl is required to make 75.0 ml of 3.50. Web according to the neutralization law, where, = molarity of concentrated hcl solution = 12.0 m. Web what volume of 12.0 m hcl is needed to contain 3.00 moles of hcl?
Web since you need $\pu{262.5 mmol}$, and the $\pu{12 m }$ solution has $\pu{12 mmol}$ per $\pu{ml}$, then you need $\pu{262.5mmol}\div \pu{12m} = \pu{21.875 ml}$ of $\pu{12 m. Web v₁ = 21.9 ml (following scientific notation, round to the nearest tenths) therefore, the volume of the 12.0 m hcl required is 21.9 ml. Calculate the molarity of 2.00 l of solution that contains 200.0 g of naoh. Web according to the neutralization law, where, = molarity of concentrated hcl solution = 12.0 m. We all know that density = mass/volume. Web since you need $\pu{262.5 mmol}$, and the $\pu{12 m }$ solution has $\pu{12 mmol}$ per $\pu{ml}$, then you need $\pu{262.5mmol}\div \pu{12m} = \pu{21.875 ml}$ of $\pu{12 m. 12 m = 12 moles hcl per 1 liter of solution.so 12 moles/ 1 liter = 3 moles/ x liters. What volume of 12.0 m hcl is required to prepare 16.0 l of 0.250 m hydrochloric acid? Ml 0.560 ml 21.9 ml 257 ml this problem has been solved! The density of your hcl is 1.179. Web what volume of 12.0 m hcl is required to make 75.0 ml of 3.50 m hcl?
