"A 45.0 mg sample of phosphorus reacts with selenium to form 131 mg of
What Is The Empirical Formula Of Phosphorus Selenide. Determine the empirical formula of phosphorus selenide. What is the empirical formula of phosphorus selenide express your answer as a chemical formula?
45.2/31 = 1.45 which is nearly 1.5 mol of p. Web a compound containing phosphorus and oxygen has a molar mass of 219.9 g / m o l and an empirical formula of $\mathrm {p}_ {2} \mat…. What is the empirical formula of phosphorus. A 1.45 − g sample of phosphorus. What is the empirical formula of the phosphorus selenide? 1 see answer advertisement w0lf93 atomic mass of phosphorous = 31g atomic mass of selenium = 79g. Atomic mass of selenium = 79g. Find the moles of each and compare to get the ratio of the. Web tants | periodic table part a a 43.6 mg sample of phosphorus reacts with selenium to form 127 mg of the compound. Web an empirical formula is one that shows the lowest whole number ratio of the elements present.
Web a compound containing phosphorus and oxygen has a molar mass of 219.9 g / m o l and an empirical formula of $\mathrm {p}_ {2} \mat…. What is the empirical formula of phosphorus selenide express your answer as a chemical formula? What is the empirical formula of the phosphorus selenide?. What is the empirical formula of the phosphorus selenide? 45.2/31 = 1.45 which is nearly 1.5 mol of p. Atomic mass of selenium = 79g. 1 see answer advertisement w0lf93 atomic mass of phosphorous = 31g atomic mass of selenium = 79g. Web so the empirical formula of the phosphorus selenide is p3se2. A 43.4 the empirical formula is p4 4 se3 3. Atomic mass of phosphorous = 31g. Web what is the empirical formula of the phosphorus selenide?
